Solve the other integral: intdx/sin^4x=intcsc^4xdx intcsc^2xcsc^2xdx Recalling that 1+cot^2x=csc^2x, rewrite: int (1+cot^2x)csc^2xdx This can be solved with a simple …

Explanation: You need to integrate this in parts. If you find the areas of the piecewise functions in sections. Then subtract the areas of sin (x). If you look at the graph it will seem clear how to go …

Rewrite as int x^2 e^(x^2/2) x dx. You may have seen some examples of integrating (x to a power times e to a power) by parts. Typically we differentiate the power of x and integrate the …

Explanation: The antiderivative cannot be calculated using u-subs, trig-subs, integration by parts, or other similar methods of integration, so I used a series representation to integrate. #int …

Apr 13, 2018 · How do you find the indefinite integral of ∫sin 4xe^sin2x dx?

How do you find the integral of ∫ dx/ (1-x)^2 from negative infinity to 0?

It's not a good idea di solve it by parts, because it is an immediate integral, using this rule: int[f(x)]^n*f'(x)dx=[f(x)]^(n+1)/(n+1)+c, so: intsinxcosxdx=sin^2x/2+c.

Apr 14, 2018 · intx/cos^2xdx=xtanx+ln|cosx|+C So, we want intx/cos^2xdx We may rewrite as intxsec^2xdx and then apply Integration by Parts. u=x du=dx dv=sec^2xdx v=tanx Note why …

Mar 25, 2018 · 2872, 1/8 (sin48-sin16) int_2^6 (8x^3+20x-2)dx= (8/4x^4+20/2x^2-2x)|_2^6 = (2x^4+10x^2-2x)|_2^6= (2 (1296)+10 (36)-12)- (2 (16)+10 (4)-4)=2940-68=2872 int_2^6cos (8x ...

Find an equation of the line through (3,7) and parallel to y=3x-4? Find the area of the region inside these curves? Jill is twice as old as her brother and half as old as her father. In 22 years, her …